If at any point on the path of a projectile its velocity is $u$ at inclination $\alpha$ then it will move at right angles to former direction after time
If at any point on the path of a projectile its velocity is $u$ at inclination $\alpha$ then it will move at right angles to former direction after time
- A
$\frac{u}{g \cos ec \alpha}$
- B
$\frac{u}{g \sin \alpha}$
- C
$\frac{u}{g \cos \alpha}$
- D
$\frac{u}{g \sec \alpha}$
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Trajectory of particle in a projectile motion is given as $y=x-\frac{x^2}{80}$. Here, $x$ and $y$ are in metre. For this projectile motion match the following with $g=10\,m / s ^2$.
$Column-I$
$Column-II$
$(A)$ Angle of projection
$(p)$ $20\,m$
$(B)$ Angle of velocity with horizontal after $4\,s$
$(q)$ $80\,m$
$(C)$ Maximum height
$(r)$ $45^{\circ}$
$(D)$ Horizontal range
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Trajectory of particle in a projectile motion is given as $y=x-\frac{x^2}{80}$. Here, $x$ and $y$ are in metre. For this projectile motion match the following with $g=10\,m / s ^2$.
| $Column-I$ | $Column-II$ |
| $(A)$ Angle of projection | $(p)$ $20\,m$ |
| $(B)$ Angle of velocity with horizontal after $4\,s$ | $(q)$ $80\,m$ |
| $(C)$ Maximum height | $(r)$ $45^{\circ}$ |
| $(D)$ Horizontal range | $(s)$ $\tan ^{-1}\left(\frac{1}{2}\right)$ |
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